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100% Real Waec Gce 2015 Physics Practical Answers.


1)
TABULATE
S/N;1,2,3,4,5
M(N):140,120,110,84,66
tita(degrees);24,32,38,51,62
Sin tita;0.4067,0.5299,0.6156,0.7771,0.8829

Note: 1cm=20N

vi) Slope(s)=(84-140)/(0.7771-0.4067)
=-56/0.3704
=-151N/degree

vii)
-I will ensure the experiment is repeated in the
specified number of times
-I will avoid error of parallax

bi)
-The total upward force must be equal to total
downward forc
-The sum of clockwise moment must be equal to
the sum of anticlockwise moment

(ii)Clockwise moment =m*10
Anticlockwise=Wsintita*40
=========================
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3a)
(i)d1=1.40cm,
d2=1.55cm,
d3=1.75cm,
d4=2.1cm,
d5=2.3cm

Real values of di
d1=1.4*0.5=0.7mm
d2=1.55*0.5=0.77mm
d3=1.75*0.5=0.875mm
d4=2.1*0.5=1.05mm
d5=2.3*0.5=1.15mm

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(ii)
Ia1=2.4A,
Ia2=3.8A,
Ia3=5.0A,
Ia4=7.4A,
Ia5=11.6A
Ib1=2.4A,
Ib2=3.6A,
Ib3=5.2A,
Ib4=7.5A,
Ib5=11.6A

(iii)
I=(Ia+Ib)/2
I1=(2.4+2.4)/2=2.4A
I2=(3.8+3.6)/2=3.7A
I3=(5.0+5.2)/2=5.1A
I4=(7.4+7.5)/2=7.45A
I5=(11.6+11.6)/2=11.6A

(3aiv)
logd1=log0.7=-0.15mm
logd2=log0.775=0.11mm
logd3=log0.875=0.06mm
logd4=log1.05=0.02mm
logd5=log1.15=0.06mm
logI1=log2.4=0.38
logI2=log3.7=0.57
logI3=log5.1=0.71
logI4=log7.45=0.87
logI5=log11.6=1.06

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(3av)
TABULATE
S/N; 1,2,,3,4,5
di(cm);1.40,1.55,1.75,2.10,2.30
di(mm);0.70,0.78,0.88,1.05,1.15
Ia(A);2.4,3.8,5.0,7.4,11.6
Ib(A);2.4,3.6,5.2,7.5,11.6
I(A);2.4,3.7,5.1,7.5,11.6
logd!(mm);-0.15,-0.11,-0.06,0.02,0.06
logI1;0.38,0.57,0.71,0.87,1.06

(vii)|Slope(s)
=change in logI/change in logd
=(0.87-0.57)/(0.02-(-0.11))
=0.3/0.13=2.3A

(vii)
-I will ensure the circuit is open when no readings
are not taken
-i will ensure tight connection

bi)
diameter(d)=1.09mm

bii)
R=eL/A
R=(5.0*10^-2*0.01)/(pie/4)*(0.001)^2
R=(5*10^-4)/(0.7855*1*10^-6)
=6.37*10^2ohm
P=I^2R
=10^2*6.37*10^2
=6.37*10^4W
============================

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